Thursday, February 11, 2010

Pareto graphs

For your variants, you need to plot out the results for cooling versus electric lighting, both in kWh/m2/year.

So for example 6, this would be as follows:

  • Total building area = 7200.00 m2
  • Simulation period = 22 days
  • Cooling: District Cooling = 46914.56 kWh
  • Therefore cooling = (46915 / 7200) * (356/22) = 105 kWh/m2/year
  • Electricity: Interior Lighting = 1834.80 kWh
  • Therefore lighting = (1834 / 7200) * (356/22) = 4 kWh/m2/year
    On the pareto graph, you are trying to minimise both, so points closer to the origin are better.

    You will notice immediately that the lighting cannot compete with the cooling. But this is only in terms of energy. There may be other reasons why you think daylight is important - e.g. the well-being of the office workers. So it is still valid to plot lighting against cooling, even though lighting uses much less energy.

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